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What is the focus of parabola X² − 4ay?
Compare the above equation with standard form of parabola x2 -4ay, we get, a 4. The co-ordinates of its vertex are (0, 0) and the co-ordinates of its focus are (0, -4); the length of its latus rectum 4a 4 u2219 4 16 units and the equation of its directrix is y a i.e., y 4 i.e., y – 4 0.
What is the parabola formula?
The parabola equation in its vertex form is y a(x – h) + k , where: a Same as the a coefficient in the standard form; h x-coordinate of the parabola vertex; and. k y-coordinate of the parabola vertex.
WHAT IS A in y2 4ax?
The equation y2 – 4ax (a x26gt; 0) represents the equation of a parabola whose co-ordinate of the vertex is at (0, 0), the co-ordinates of the focus are (- a, 0), the equation of directrix is x a or x – a 0, the equation of the axis is y 0, the axis is along negative x-axis; the length of its latus rectum is 4a and
What is the equation of Latus Rectum of x2 4ay?
4.6.Equationx2 4ay;Vertex(0, 0)Focus(0, a)Equation of the directrixy -aEquation of the axisx 02 more rows
What is the focus of parabola x2 4ay?
The directrix of the parabola x2 4ay, having y-axis as its axis, passes through (0, -a), and has the equation y + a 0. The focus of the parabola x2 -4ay, having y-axis as its axis, passes through (0, a), and has the equation y – a 0
How do you find the focus of a parabola?
Finding the focus of a parabola given its equation If you have the equation of a parabola in vertex form ya(xu2212h)2+k, then the vertex is at (h,k) and the focus is (h,k+14a).
What is the focus of this parabola?
In order to find the focus of a parabola, you must know that the equation of a parabola in a vertex form is ya(xu2212h)2+k where a represents the slope of the equation. From the formula, we can see that the coordinates for the focus of the parabola is (h, k+1/4a)
Where is the opening of the parabola x2 4ay?
(0,a) and yu2212a0.
