# What is the factor of x 2 25?

## What is the factor of x 2 25?

For example, xxb2-25 can be factored as (x+5)(x-5).

## Is X 2 25 A perfect square trinomial?

Yes, x2+10x+25 is a perfect square trinomial.

## How many solutions does x 2 =- 25 have?

The equation has no real solutions. It has 2 imaginary, or complex solutions.

## Is X squared plus 25 Factorable?

122 – 52 144 – 25 119 (12 – 5)(12 + 5) 7 xd7 17. This is certainly not what you are looking for and thus we say x2 + 25 doesn’t factor

## Why can x 2 25 not be factored?

Explanation: Notice that if x is Real then x2u22650 , so x2+25 has no linear factors with Real coefficients.

## How do you calculate x2 25?

Yes, x2+10x+25 is a perfect square trinomial.

## Can you factor 25x 2?

Rewrite 25 as 52 . Since both terms are perfect squares, factor using the difference of squares formula, a2u2212b2(a+b)(au2212b) a 2 – b 2 ( a + b ) ( a – b ) where a5 and bx .

## How do you know if a trinomial is a perfect square?

A trinomial is a perfect square trinomial if it can be factored into a binomial multiplied to itself. (This is the part where you are moving the other way). In a perfect square trinomial, two of your terms will be perfect squares.

## What is the perfect square of x 2 10x 25?

For example, x2 14x + 49 and x2 + 14x + 49 are both perfect square trinomials. Both x2 and 49 are perfect squares.

## Is X 2 a perfect square trinomial?

For example, xxb2-25 can be factored as (x+5)(x-5).

## What are the solutions of x 2 25?

Two solutions were found :

x = 5x = -5.

## How many solutions does X² =- 16 have?

two solutions
If we have the equation x2 = 16, what are the solutions to the equation? Since the square of a positive or negative number are always positive, this equation has two solutions, namely x = -4 or x = 4.

## What are the factors of x2 − 25?

If we expand (a+b)(a-b) we will get axb2-bxb2. Factorization goes the other way: suppose we have an expression that is the difference of two squares, like xxb2-25 or 49xxb2-yxb2, then we can factor is using the roots of those squares. For example, xxb2-25 can be factored as (x+5)(x-5).

## How much Solutions does an equation have?

If solving an equation yields a statement that is true for a single value for the variable, like x 3, then the equation has one solution. If solving an equation yields a statement that is always true, like 3 3, then the equation has infinitely many solutions

## Can X squared plus 25 be factored?

When an expression can be viewed as the difference of two perfect squares, i.e. axb2-bxb2, then we can factor it as (a+b)(a-b). For example, xxb2-25 can be factored as (x+5)(x-5). This method is based on the pattern (a+b)(a-b)axb2-bxb2, which can be verified by expanding the parentheses in (a+b)(a-b).

## How do you Factorise x squared 25?

For example, x²-25 can be factored as (x+5)(x-5).

## Can x 2 +25 be factored?

If we expand (a+b)(a-b) we will get axb2-bxb2. Factorization goes the other way: suppose we have an expression that is the difference of two squares, like xxb2-25 or 49xxb2-yxb2, then we can factor is using the roots of those squares. For example, xxb2-25 can be factored as (x+5)(x-5).

## Can you factor x 25?

Prime numbers have two factors, themselves and 1, but those are the trivial factors that every number has. Because they cannot be factored in any other way, we say that they cannot be factored.

## What is it called when a number Cannot be factored?

A polynomial with integer coefficients that cannot be factored into polynomials of lower degree , also with integer coefficients, is called an irreducible or prime polynomial . is an irreducible polynomial.

## What is the best method to solve x2 25?

There are two ways of doing this. Method 1. Add 25 to both sides. x2−25+25=25. but −25+25=0. x2=25. x=√25=±5

## How many solutions does x2 25 have?

The equation has no real solutions. It has 2 imaginary, or complex solutions.

## Can 25x squared be factored?

Rewrite 25 as 52 . Since both terms are perfect squares, factor using the difference of squares formula, a2−b2=(a+b)(a−b) a 2 – b 2 = ( a + b ) ( a – b ) where a=5 and b=x .