# How do you solve x 2 6x 4?

## How do you solve x 2 6x 4?

• Force a perfect square trinomial such that a2+2ab+b2(a+b)2 on the left side of the equation.
• Add 4 to both sides of the equation.
• Take the coefficient of the x term and divide it by 2 and square the result.
• Add 9 to both sides.
• Subtract 3 from both sides.

## Is x2 6x 4 0 a quadratic equation?

Now, the above equation clearly represents a quadratic equation of the form ax2 + bx + c 0, where a 1, b 6 and c -4. Hence, the above equation is a quadratic equation.

## What are the roots of the equation x2 6x 4?

The roots of the equation x2 + 6x 4 0 are u03b1, u03b2.

## What is the nature of the roots of quadratic equation x 2 6x 4 0?

Roots of equation are real.

## How do you solve for x in a quadratic equation?

The roots of the equation x2 + 6x 4 0 are u03b1, u03b2.

## How do you solve x squared 6x?

(x ^{2} – 6x + 4 0) is a quadratic equation.

## How do you tell if a function is quadratic from an equation?

Definition of quadratic equation : any equation containing one term in which the unknown is squared and no term in which it is raised to a higher power solve for x in the quadratic equation x2 + 4x + 4 0.

## What is considered a quadratic equation?

Examples of quadratic equations in other forms include: x(x – 2) 4 [upon multiplying and moving the 4, becomes xxb2 – 2x – 4 0] x(2x + 3) 12 [upon multiplying and moving the 12, becomes 2xxb2 – 3x – 12 0] 3x(x + 8) -2 [upon multiplying and moving the -2, becomes 3xxb2 + 24x + 2 0]

## What is a good example of a quadratic equation?

u21d2 4 x 11 Thus, x2 + 4x 11 + x2 is not a quadratic equation. can be written as x 2 u2212 4 x + 0 0 So, x 2 u2212 4 x is a quadratic equation.

## How do you find roots of an equation?

The roots are calculated using the formula, x (-b xb1 u221a (bxb2 – 4ac) )/2a. Discriminant is, D b2 – 4ac. If D x26gt; 0, then the equation has two real and distinct roots. If D x26lt; 0, the equation has two complex roots.

## What are the solutions roots of the equation?

Now, the above equation clearly represents a quadratic equation of the form ax2 + bx + c 0, where a 1, b 6 and c -4. Hence, the above equation is a quadratic equation.

## What is the nature of the roots of the quadratic equation x 2 4x 4 0?

, then roots are real and equal.

## What are the roots of the equation x2 6x 4 0?

The roots of the equation x2 + 6x 4 0 are u03b1, u03b2.

## What are the nature of roots of quadratic equation?

We can see, the discriminant of the given quadratic equation is positive but not a perfect square. Hence, the roots of a quadratic equation are real, unequal and irrational

## What is the nature of roots of the quadratic equation 4x 2 2x 3 0?

then from equation (I) we can say that nature of the roots of the equation 4×2 – 2x – 3 0 is real, irrational and unequal.

## How do you find the X in a quadratic equation?

The Solve by Factoring process will require four major steps:

• Move all terms to one side of the equation, usually the left, using addition or subtraction.
• Factor the equation completely.
• Set each factor equal to zero, and solve.
• List each solution from Step 3 as a solution to the original equation.

## How do you solve for x factoring?

The four methods of solving a quadratic equation are factoring, using the square roots, completing the square and the quadratic formula.

## How do you factor X squared 6x?

The solutions to x2 – 6x 16 are x -2 and x 8.