How do you solve x 2 6x 10?

How do you solve x 2 6x 10?

Explanation:
  1. x2+ax+b=(x+c)2+d.
  2. a=6→c=3. (x+3)2=x2+6x+9.
  3. x2+6x+10=(x+3)2+1.
  4. (x+3)2+1=0. (x+3)2=−1. x+3=√−1=±i. x=±i−3.

What is the nature of the roots of the quadratic equation x 2 6x 10 0?

Compare by general equation ax2 + bx + c = 0. Hence the roots are real and equal.

How do you solve x 2 6x 10 0?

Step by step solution :
  1. Step 1 :Trying to factor by splitting the middle term. 1.1 Factoring x2-6x+10. The middle term is, -6x its coefficient is -6 . The last term, “the constant”, is +10.
  2. Step 2 : Parabola, Finding the Vertex: 2.1 Find the Vertex of y = x2-6x+10. In our case the x coordinate is 3.0000.

How do you solve for x in a quadratic equation?

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