At what rate is the area increasing when the side length is 6 cm?

At what rate is the area increasing when the side length is 6 cm?

It turns out that 1,296 / 36 36. So, if you increase the length of a square’s sides by 6 times, the area increases by its square, or 36.

What rate is the area of the square increasing?

At any given time, each side of the square is increasing at the rate of 4 cm / s ( dx / dt). I hope this helps you.

How do you find the rate of change of the perimeter of a square?

To solve this problem you are dealing with perimeter (P) and area (A) and time (t) is implied. So the change in perimeter with respect to time is dP/dt and the change in area with respect to time is dA/dt.

What is the area of square formula?

The area of a square is calculated with the help of the formula: Area s xd7 s, where, ‘s’ is one side of the square. Since the area of a square is a two-dimensional quantity, it is always expressed in square units.

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